stripe.rb in pay-7.0.0

- old
+ new

@@ -28,11 +28,11 @@
       autoload :SubscriptionTrialWillEnd, "pay/stripe/webhooks/subscription_trial_will_end"
     end
 
     extend Env
 
-    REQUIRED_VERSION = "~> 9"
+    REQUIRED_VERSION = "~> 10"
 
     # A list of database model names that include Pay
     # Used for safely looking up models with client_reference_id
     mattr_accessor :model_names, default: Set.new
 
@@ -42,11 +42,10 @@
       Pay::Engine.version_matches?(required: REQUIRED_VERSION, current: ::Stripe::VERSION) || (raise "[Pay] stripe gem must be version #{REQUIRED_VERSION}")
     end
 
     def self.setup
       ::Stripe.api_key = private_key
-      ::Stripe.api_version ||= "2023-08-16"
 
       # Used by Stripe to identify Pay for support
       ::Stripe.set_app_info("PayRails", partner_id: "pp_partner_IqhY0UExnJYLxg", version: Pay::VERSION, url: "https://github.com/pay-rails/pay")
 
       # Automatically retry requests that fail
@@ -121,16 +120,16 @@
       end
     end
 
     def self.to_client_reference_id(record)
       raise ArgumentError, "#{record.class.name} does not include Pay. Allowed models: #{model_names.to_a.join(", ")}" unless model_names.include?(record.class.name)
-      [record.class.name, record.id].join("/")
+      [record.class.name, record.id].join("_")
     end
 
     def self.find_by_client_reference_id(client_reference_id)
       # If there is a client reference ID, make sure we have a Pay::Customer record
       # client_reference_id should be in the format of "User/1"
-      model_name, id = client_reference_id.split("/", 2)
+      model_name, id = client_reference_id.split("_", 2)
 
       # Only allow model names that use Pay
       return unless model_names.include?(model_name)
 
       model_name.constantize.find(id)