import "number"; d3.interpolateString = d3_interpolateString; function d3_interpolateString(a, b) { var m, // current match i, // current index j, // current index (for coalescing) s0 = 0, // start index of current string prefix s1 = 0, // end index of current string prefix s = [], // string constants and placeholders q = [], // number interpolators n, // q.length o; // Coerce inputs to strings. a = a + "", b = b + ""; // Reset our regular expression! d3_interpolate_number.lastIndex = 0; // Find all numbers in b. for (i = 0; m = d3_interpolate_number.exec(b); ++i) { if (m.index) s.push(b.substring(s0, s1 = m.index)); q.push({i: s.length, x: m[0]}); s.push(null); s0 = d3_interpolate_number.lastIndex; } if (s0 < b.length) s.push(b.substring(s0)); // Find all numbers in a. for (i = 0, n = q.length; (m = d3_interpolate_number.exec(a)) && i < n; ++i) { o = q[i]; if (o.x == m[0]) { // The numbers match, so coalesce. if (o.i) { if (s[o.i + 1] == null) { // This match is followed by another number. s[o.i - 1] += o.x; s.splice(o.i, 1); for (j = i + 1; j < n; ++j) q[j].i--; } else { // This match is followed by a string, so coalesce twice. s[o.i - 1] += o.x + s[o.i + 1]; s.splice(o.i, 2); for (j = i + 1; j < n; ++j) q[j].i -= 2; } } else { if (s[o.i + 1] == null) { // This match is followed by another number. s[o.i] = o.x; } else { // This match is followed by a string, so coalesce twice. s[o.i] = o.x + s[o.i + 1]; s.splice(o.i + 1, 1); for (j = i + 1; j < n; ++j) q[j].i--; } } q.splice(i, 1); n--; i--; } else { o.x = d3_interpolateNumber(parseFloat(m[0]), parseFloat(o.x)); } } // Remove any numbers in b not found in a. while (i < n) { o = q.pop(); if (s[o.i + 1] == null) { // This match is followed by another number. s[o.i] = o.x; } else { // This match is followed by a string, so coalesce twice. s[o.i] = o.x + s[o.i + 1]; s.splice(o.i + 1, 1); } n--; } // Special optimization for only a single match. if (s.length === 1) { return s[0] == null ? (o = q[0].x, function(t) { return o(t) + ""; }) : function() { return b; }; } // Otherwise, interpolate each of the numbers and rejoin the string. return function(t) { for (i = 0; i < n; ++i) s[(o = q[i]).i] = o.x(t); return s.join(""); }; } var d3_interpolate_number = /[-+]?(?:\d+\.?\d*|\.?\d+)(?:[eE][-+]?\d+)?/g;