/*
* Copyright 2016-2018 Uber Technologies, Inc.
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
/** @file algos.c
* @brief Hexagon grid algorithms
*/
#include "algos.h"
#include <float.h>
#include <math.h>
#include <stdbool.h>
#include <stdlib.h>
#include "baseCells.h"
#include "bbox.h"
#include "faceijk.h"
#include "geoCoord.h"
#include "h3Index.h"
#include "h3api.h"
#include "linkedGeo.h"
#include "polygon.h"
#include "stackAlloc.h"
#include "vertexGraph.h"
/*
* Return codes from hexRange and related functions.
*/
#define HEX_RANGE_SUCCESS 0
#define HEX_RANGE_PENTAGON 1
#define HEX_RANGE_K_SUBSEQUENCE 2
/**
* Directions used for traversing a hexagonal ring counterclockwise around
* {1, 0, 0}
*
* <pre>
* _
* _/ \\_
* / \\5/ \\
* \\0/ \\4/
* / \\_/ \\
* \\1/ \\3/
* \\2/
* </pre>
*/
static const Direction DIRECTIONS[6] = {J_AXES_DIGIT, JK_AXES_DIGIT,
K_AXES_DIGIT, IK_AXES_DIGIT,
I_AXES_DIGIT, IJ_AXES_DIGIT};
/**
* Direction used for traversing to the next outward hexagonal ring.
*/
static const Direction NEXT_RING_DIRECTION = I_AXES_DIGIT;
/**
* New digit when traversing along class II grids.
*
* Current digit -> direction -> new digit.
*/
static const Direction NEW_DIGIT_II[7][7] = {
{CENTER_DIGIT, K_AXES_DIGIT, J_AXES_DIGIT, JK_AXES_DIGIT, I_AXES_DIGIT,
IK_AXES_DIGIT, IJ_AXES_DIGIT},
{K_AXES_DIGIT, I_AXES_DIGIT, JK_AXES_DIGIT, IJ_AXES_DIGIT, IK_AXES_DIGIT,
J_AXES_DIGIT, CENTER_DIGIT},
{J_AXES_DIGIT, JK_AXES_DIGIT, K_AXES_DIGIT, I_AXES_DIGIT, IJ_AXES_DIGIT,
CENTER_DIGIT, IK_AXES_DIGIT},
{JK_AXES_DIGIT, IJ_AXES_DIGIT, I_AXES_DIGIT, IK_AXES_DIGIT, CENTER_DIGIT,
K_AXES_DIGIT, J_AXES_DIGIT},
{I_AXES_DIGIT, IK_AXES_DIGIT, IJ_AXES_DIGIT, CENTER_DIGIT, J_AXES_DIGIT,
JK_AXES_DIGIT, K_AXES_DIGIT},
{IK_AXES_DIGIT, J_AXES_DIGIT, CENTER_DIGIT, K_AXES_DIGIT, JK_AXES_DIGIT,
IJ_AXES_DIGIT, I_AXES_DIGIT},
{IJ_AXES_DIGIT, CENTER_DIGIT, IK_AXES_DIGIT, J_AXES_DIGIT, K_AXES_DIGIT,
I_AXES_DIGIT, JK_AXES_DIGIT}};
/**
* New traversal direction when traversing along class II grids.
*
* Current digit -> direction -> new ap7 move (at coarser level).
*/
static const Direction NEW_ADJUSTMENT_II[7][7] = {
{CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT,
CENTER_DIGIT, CENTER_DIGIT},
{CENTER_DIGIT, K_AXES_DIGIT, CENTER_DIGIT, K_AXES_DIGIT, CENTER_DIGIT,
IK_AXES_DIGIT, CENTER_DIGIT},
{CENTER_DIGIT, CENTER_DIGIT, J_AXES_DIGIT, JK_AXES_DIGIT, CENTER_DIGIT,
CENTER_DIGIT, J_AXES_DIGIT},
{CENTER_DIGIT, K_AXES_DIGIT, JK_AXES_DIGIT, JK_AXES_DIGIT, CENTER_DIGIT,
CENTER_DIGIT, CENTER_DIGIT},
{CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT, I_AXES_DIGIT,
I_AXES_DIGIT, IJ_AXES_DIGIT},
{CENTER_DIGIT, IK_AXES_DIGIT, CENTER_DIGIT, CENTER_DIGIT, I_AXES_DIGIT,
IK_AXES_DIGIT, CENTER_DIGIT},
{CENTER_DIGIT, CENTER_DIGIT, J_AXES_DIGIT, CENTER_DIGIT, IJ_AXES_DIGIT,
CENTER_DIGIT, IJ_AXES_DIGIT}};
/**
* New traversal direction when traversing along class III grids.
*
* Current digit -> direction -> new ap7 move (at coarser level).
*/
static const Direction NEW_DIGIT_III[7][7] = {
{CENTER_DIGIT, K_AXES_DIGIT, J_AXES_DIGIT, JK_AXES_DIGIT, I_AXES_DIGIT,
IK_AXES_DIGIT, IJ_AXES_DIGIT},
{K_AXES_DIGIT, J_AXES_DIGIT, JK_AXES_DIGIT, I_AXES_DIGIT, IK_AXES_DIGIT,
IJ_AXES_DIGIT, CENTER_DIGIT},
{J_AXES_DIGIT, JK_AXES_DIGIT, I_AXES_DIGIT, IK_AXES_DIGIT, IJ_AXES_DIGIT,
CENTER_DIGIT, K_AXES_DIGIT},
{JK_AXES_DIGIT, I_AXES_DIGIT, IK_AXES_DIGIT, IJ_AXES_DIGIT, CENTER_DIGIT,
K_AXES_DIGIT, J_AXES_DIGIT},
{I_AXES_DIGIT, IK_AXES_DIGIT, IJ_AXES_DIGIT, CENTER_DIGIT, K_AXES_DIGIT,
J_AXES_DIGIT, JK_AXES_DIGIT},
{IK_AXES_DIGIT, IJ_AXES_DIGIT, CENTER_DIGIT, K_AXES_DIGIT, J_AXES_DIGIT,
JK_AXES_DIGIT, I_AXES_DIGIT},
{IJ_AXES_DIGIT, CENTER_DIGIT, K_AXES_DIGIT, J_AXES_DIGIT, JK_AXES_DIGIT,
I_AXES_DIGIT, IK_AXES_DIGIT}};
/**
* New traversal direction when traversing along class III grids.
*
* Current digit -> direction -> new ap7 move (at coarser level).
*/
static const Direction NEW_ADJUSTMENT_III[7][7] = {
{CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT,
CENTER_DIGIT, CENTER_DIGIT},
{CENTER_DIGIT, K_AXES_DIGIT, CENTER_DIGIT, JK_AXES_DIGIT, CENTER_DIGIT,
K_AXES_DIGIT, CENTER_DIGIT},
{CENTER_DIGIT, CENTER_DIGIT, J_AXES_DIGIT, J_AXES_DIGIT, CENTER_DIGIT,
CENTER_DIGIT, IJ_AXES_DIGIT},
{CENTER_DIGIT, JK_AXES_DIGIT, J_AXES_DIGIT, JK_AXES_DIGIT, CENTER_DIGIT,
CENTER_DIGIT, CENTER_DIGIT},
{CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT, CENTER_DIGIT, I_AXES_DIGIT,
IK_AXES_DIGIT, I_AXES_DIGIT},
{CENTER_DIGIT, K_AXES_DIGIT, CENTER_DIGIT, CENTER_DIGIT, IK_AXES_DIGIT,
IK_AXES_DIGIT, CENTER_DIGIT},
{CENTER_DIGIT, CENTER_DIGIT, IJ_AXES_DIGIT, CENTER_DIGIT, I_AXES_DIGIT,
CENTER_DIGIT, IJ_AXES_DIGIT}};
/**
* Maximum number of indices that result from the kRing algorithm with the given
* k. Formula source and proof: https://oeis.org/A003215
*
* @param k k value, k >= 0.
*/
int H3_EXPORT(maxKringSize)(int k) { return 3 * k * (k + 1) + 1; }
/**
* k-rings produces indices within k distance of the origin index.
*
* k-ring 0 is defined as the origin index, k-ring 1 is defined as k-ring 0 and
* all neighboring indices, and so on.
*
* Output is placed in the provided array in no particular order. Elements of
* the output array may be left zero, as can happen when crossing a pentagon.
*
* @param origin Origin location.
* @param k k >= 0
* @param out Zero-filled array which must be of size maxKringSize(k).
*/
void H3_EXPORT(kRing)(H3Index origin, int k, H3Index* out) {
int maxIdx = H3_EXPORT(maxKringSize)(k);
int* distances = malloc(maxIdx * sizeof(int));
H3_EXPORT(kRingDistances)(origin, k, out, distances);
free(distances);
}
/**
* k-rings produces indices within k distance of the origin index.
*
* k-ring 0 is defined as the origin index, k-ring 1 is defined as k-ring 0 and
* all neighboring indices, and so on.
*
* Output is placed in the provided array in no particular order. Elements of
* the output array may be left zero, as can happen when crossing a pentagon.
*
* @param origin Origin location.
* @param k k >= 0
* @param out Zero-filled array which must be of size maxKringSize(k).
* @param distances Zero-filled array which must be of size maxKringSize(k).
*/
void H3_EXPORT(kRingDistances)(H3Index origin, int k, H3Index* out,
int* distances) {
const int maxIdx = H3_EXPORT(maxKringSize)(k);
// Optimistically try the faster hexRange algorithm first
const bool failed = H3_EXPORT(hexRangeDistances)(origin, k, out, distances);
if (failed) {
// Fast algo failed, fall back to slower, correct algo
// and also wipe out array because contents untrustworthy
memset(out, 0, maxIdx * sizeof(out[0]));
memset(distances, 0, maxIdx * sizeof(distances[0]));
_kRingInternal(origin, k, out, distances, maxIdx, 0);
}
}
/**
* Internal helper function called recursively for kRingDistances.
*
* Adds the origin index to the output set (treating it as a hash set)
* and recurses to its neighbors, if needed.
*
* @param origin
* @param k Maximum distance to move from the origin.
* @param out Array treated as a hash set, elements being either H3Index or 0.
* @param distances Scratch area, with elements paralleling the out array.
* Elements indicate ijk distance from the origin index to the output index.
* @param maxIdx Size of out and scratch arrays (must be maxKringSize(k))
* @param curK Current distance from the origin.
*/
void _kRingInternal(H3Index origin, int k, H3Index* out, int* distances,
int maxIdx, int curK) {
if (origin == 0) return;
// Put origin in the output array. out is used as a hash set.
int off = origin % maxIdx;
while (out[off] != 0 && out[off] != origin) {
off = (off + 1) % maxIdx;
}
// We either got a free slot in the hash set or hit a duplicate
// We might need to process the duplicate anyways because we got
// here on a longer path before.
if (out[off] == origin && distances[off] <= curK) return;
out[off] = origin;
distances[off] = curK;
// Base case: reached an index k away from the origin.
if (curK >= k) return;
// Recurse to all neighbors in no particular order.
for (int i = 0; i < 6; i++) {
int rotations = 0;
_kRingInternal(h3NeighborRotations(origin, DIRECTIONS[i], &rotations),
k, out, distances, maxIdx, curK + 1);
}
}
/**
* Returns the hexagon index neighboring the origin, in the direction dir.
*
* Implementation note: The only reachable case where this returns 0 is if the
* origin is a pentagon and the translation is in the k direction. Thus,
* 0 can only be returned if origin is a pentagon.
*
* @param origin Origin index
* @param dir Direction to move in
* @param rotations Number of ccw rotations to perform to reorient the
* translation vector. Will be modified to the new number of
* rotations to perform (such as when crossing a face edge.)
* @return H3Index of the specified neighbor or 0 if deleted k-subsequence
* distortion is encountered.
*/
H3Index h3NeighborRotations(H3Index origin, Direction dir, int* rotations) {
H3Index out = origin;
for (int i = 0; i < *rotations; i++) {
dir = _rotate60ccw(dir);
}
int newRotations = 0;
int oldBaseCell = H3_GET_BASE_CELL(out);
Direction oldLeadingDigit = _h3LeadingNonZeroDigit(out);
// Adjust the indexing digits and, if needed, the base cell.
int r = H3_GET_RESOLUTION(out) - 1;
while (true) {
if (r == -1) {
H3_SET_BASE_CELL(out, baseCellNeighbors[oldBaseCell][dir]);
newRotations = baseCellNeighbor60CCWRots[oldBaseCell][dir];
if (H3_GET_BASE_CELL(out) == INVALID_BASE_CELL) {
// Adjust for the deleted k vertex at the base cell level.
// This edge actually borders a different neighbor.
H3_SET_BASE_CELL(out,
baseCellNeighbors[oldBaseCell][IK_AXES_DIGIT]);
newRotations =
baseCellNeighbor60CCWRots[oldBaseCell][IK_AXES_DIGIT];
// perform the adjustment for the k-subsequence we're skipping
// over.
out = _h3Rotate60ccw(out);
*rotations = *rotations + 1;
}
break;
} else {
Direction oldDigit = H3_GET_INDEX_DIGIT(out, r + 1);
Direction nextDir;
if (isResClassIII(r + 1)) {
H3_SET_INDEX_DIGIT(out, r + 1, NEW_DIGIT_II[oldDigit][dir]);
nextDir = NEW_ADJUSTMENT_II[oldDigit][dir];
} else {
H3_SET_INDEX_DIGIT(out, r + 1, NEW_DIGIT_III[oldDigit][dir]);
nextDir = NEW_ADJUSTMENT_III[oldDigit][dir];
}
if (nextDir != CENTER_DIGIT) {
dir = nextDir;
r--;
} else {
// No more adjustment to perform
break;
}
}
}
int newBaseCell = H3_GET_BASE_CELL(out);
if (_isBaseCellPentagon(newBaseCell)) {
int alreadyAdjustedKSubsequence = 0;
// force rotation out of missing k-axes sub-sequence
if (_h3LeadingNonZeroDigit(out) == K_AXES_DIGIT) {
if (oldBaseCell != newBaseCell) {
// in this case, we traversed into the deleted
// k subsequence of a pentagon base cell.
// We need to rotate out of that case depending
// on how we got here.
// check for a cw/ccw offset face; default is ccw
if (_baseCellIsCwOffset(
newBaseCell, baseCellData[oldBaseCell].homeFijk.face)) {
out = _h3Rotate60cw(out);
} else {
// See cwOffsetPent in testKRing.c for why this is
// unreachable.
out = _h3Rotate60ccw(out); // LCOV_EXCL_LINE
}
alreadyAdjustedKSubsequence = 1;
} else {
// In this case, we traversed into the deleted
// k subsequence from within the same pentagon
// base cell.
if (oldLeadingDigit == CENTER_DIGIT) {
// Undefined: the k direction is deleted from here
return H3_INVALID_INDEX;
} else if (oldLeadingDigit == JK_AXES_DIGIT) {
// Rotate out of the deleted k subsequence
// We also need an additional change to the direction we're
// moving in
out = _h3Rotate60ccw(out);
*rotations = *rotations + 1;
} else if (oldLeadingDigit == IK_AXES_DIGIT) {
// Rotate out of the deleted k subsequence
// We also need an additional change to the direction we're
// moving in
out = _h3Rotate60cw(out);
*rotations = *rotations + 5;
} else {
// Should never occur
return H3_INVALID_INDEX; // LCOV_EXCL_LINE
}
}
}
for (int i = 0; i < newRotations; i++) out = _h3RotatePent60ccw(out);
// Account for differing orientation of the base cells (this edge
// might not follow properties of some other edges.)
if (oldBaseCell != newBaseCell) {
if (_isBaseCellPolarPentagon(newBaseCell)) {
// 'polar' base cells behave differently because they have all
// i neighbors.
if (oldBaseCell != 118 && oldBaseCell != 8 &&
_h3LeadingNonZeroDigit(out) != JK_AXES_DIGIT) {
*rotations = *rotations + 1;
}
} else if (_h3LeadingNonZeroDigit(out) == IK_AXES_DIGIT &&
!alreadyAdjustedKSubsequence) {
// account for distortion introduced to the 5 neighbor by the
// deleted k subsequence.
*rotations = *rotations + 1;
}
}
} else {
for (int i = 0; i < newRotations; i++) out = _h3Rotate60ccw(out);
}
*rotations = (*rotations + newRotations) % 6;
return out;
}
/**
* hexRange produces indexes within k distance of the origin index.
* Output behavior is undefined when one of the indexes returned by this
* function is a pentagon or is in the pentagon distortion area.
*
* k-ring 0 is defined as the origin index, k-ring 1 is defined as k-ring 0 and
* all neighboring indexes, and so on.
*
* Output is placed in the provided array in order of increasing distance from
* the origin.
*
* @param origin Origin location.
* @param k k >= 0
* @param out Array which must be of size maxKringSize(k).
* @return 0 if no pentagon or pentagonal distortion area was encountered.
*/
int H3_EXPORT(hexRange)(H3Index origin, int k, H3Index* out) {
return H3_EXPORT(hexRangeDistances)(origin, k, out, 0);
}
/**
* hexRange produces indexes within k distance of the origin index.
* Output behavior is undefined when one of the indexes returned by this
* function is a pentagon or is in the pentagon distortion area.
*
* k-ring 0 is defined as the origin index, k-ring 1 is defined as k-ring 0 and
* all neighboring indexes, and so on.
*
* Output is placed in the provided array in order of increasing distance from
* the origin. The distances in hexagons is placed in the distances array at
* the same offset.
*
* @param origin Origin location.
* @param k k >= 0
* @param out Array which must be of size maxKringSize(k).
* @param distances Null or array which must be of size maxKringSize(k).
* @return 0 if no pentagon or pentagonal distortion area was encountered.
*/
int H3_EXPORT(hexRangeDistances)(H3Index origin, int k, H3Index* out,
int* distances) {
// Return codes:
// 1 Pentagon was encountered
// 2 Pentagon distortion (deleted k subsequence) was encountered
// Pentagon being encountered is not itself a problem; really the deleted
// k-subsequence is the problem, but for compatibility reasons we fail on
// the pentagon.
// k must be >= 0, so origin is always needed
int idx = 0;
out[idx] = origin;
if (distances) {
distances[idx] = 0;
}
idx++;
if (H3_EXPORT(h3IsPentagon)(origin)) {
// Pentagon was encountered; bail out as user doesn't want this.
return HEX_RANGE_PENTAGON;
}
// 0 < ring <= k, current ring
int ring = 1;
// 0 <= direction < 6, current side of the ring
int direction = 0;
// 0 <= i < ring, current position on the side of the ring
int i = 0;
// Number of 60 degree ccw rotations to perform on the direction (based on
// which faces have been crossed.)
int rotations = 0;
while (ring <= k) {
if (direction == 0 && i == 0) {
// Not putting in the output set as it will be done later, at
// the end of this ring.
origin =
h3NeighborRotations(origin, NEXT_RING_DIRECTION, &rotations);
if (origin == 0) {
// Should not be possible because `origin` would have to be a
// pentagon
return HEX_RANGE_K_SUBSEQUENCE; // LCOV_EXCL_LINE
}
if (H3_EXPORT(h3IsPentagon)(origin)) {
// Pentagon was encountered; bail out as user doesn't want this.
return HEX_RANGE_PENTAGON;
}
}
origin = h3NeighborRotations(origin, DIRECTIONS[direction], &rotations);
if (origin == 0) {
// Should not be possible because `origin` would have to be a
// pentagon
return HEX_RANGE_K_SUBSEQUENCE; // LCOV_EXCL_LINE
}
out[idx] = origin;
if (distances) {
distances[idx] = ring;
}
idx++;
i++;
// Check if end of this side of the k-ring
if (i == ring) {
i = 0;
direction++;
// Check if end of this ring.
if (direction == 6) {
direction = 0;
ring++;
}
}
if (H3_EXPORT(h3IsPentagon)(origin)) {
// Pentagon was encountered; bail out as user doesn't want this.
return HEX_RANGE_PENTAGON;
}
}
return HEX_RANGE_SUCCESS;
}
/**
* hexRanges takes an array of input hex IDs and a max k-ring and returns an
* array of hexagon IDs sorted first by the original hex IDs and then by the
* k-ring (0 to max), with no guaranteed sorting within each k-ring group.
*
* @param h3Set A pointer to an array of H3Indexes
* @param length The total number of H3Indexes in h3Set
* @param k The number of rings to generate
* @param out A pointer to the output memory to dump the new set of H3Indexes to
* The memory block should be equal to maxKringSize(k) * length
* @return 0 if no pentagon is encountered. Cannot trust output otherwise
*/
int H3_EXPORT(hexRanges)(H3Index* h3Set, int length, int k, H3Index* out) {
int success = 0;
H3Index* segment;
int segmentSize = H3_EXPORT(maxKringSize)(k);
for (int i = 0; i < length; i++) {
// Determine the appropriate segment of the output array to operate on
segment = out + i * segmentSize;
success = H3_EXPORT(hexRange)(h3Set[i], k, segment);
if (success != 0) return success;
}
return 0;
}
/**
* Returns the hollow hexagonal ring centered at origin with sides of length k.
*
* @param origin Origin location.
* @param k k >= 0
* @param out Array which must be of size 6 * k (or 1 if k == 0)
* @return 0 if no pentagonal distortion was encountered.
*/
int H3_EXPORT(hexRing)(H3Index origin, int k, H3Index* out) {
// Short-circuit on 'identity' ring
if (k == 0) {
out[0] = origin;
return 0;
}
int idx = 0;
// Number of 60 degree ccw rotations to perform on the direction (based on
// which faces have been crossed.)
int rotations = 0;
// Scratch structure for checking for pentagons
if (H3_EXPORT(h3IsPentagon)(origin)) {
// Pentagon was encountered; bail out as user doesn't want this.
return HEX_RANGE_PENTAGON;
}
for (int ring = 0; ring < k; ring++) {
origin = h3NeighborRotations(origin, NEXT_RING_DIRECTION, &rotations);
if (origin == 0) {
// Should not be possible because `origin` would have to be a
// pentagon
return HEX_RANGE_K_SUBSEQUENCE; // LCOV_EXCL_LINE
}
if (H3_EXPORT(h3IsPentagon)(origin)) {
return HEX_RANGE_PENTAGON;
}
}
H3Index lastIndex = origin;
out[idx] = origin;
idx++;
for (int direction = 0; direction < 6; direction++) {
for (int pos = 0; pos < k; pos++) {
origin =
h3NeighborRotations(origin, DIRECTIONS[direction], &rotations);
if (origin == 0) {
// Should not be possible because `origin` would have to be a
// pentagon
return HEX_RANGE_K_SUBSEQUENCE; // LCOV_EXCL_LINE
}
// Skip the very last index, it was already added. We do
// however need to traverse to it because of the pentagonal
// distortion check, below.
if (pos != k - 1 || direction != 5) {
out[idx] = origin;
idx++;
if (H3_EXPORT(h3IsPentagon)(origin)) {
return HEX_RANGE_PENTAGON;
}
}
}
}
// Check that this matches the expected lastIndex, if it doesn't,
// it indicates pentagonal distortion occurred and we should report
// failure.
if (lastIndex != origin) {
return HEX_RANGE_PENTAGON;
} else {
return HEX_RANGE_SUCCESS;
}
}
/**
* maxPolyfillSize returns the number of hexagons to allocate space for when
* performing a polyfill on the given GeoJSON-like data structure.
*
* Currently a laughably padded response, being a k-ring that wholly contains
* a bounding box of the GeoJSON, but still less wasted memory than initializing
* a Python application? ;)
*
* @param geoPolygon A GeoJSON-like data structure indicating the poly to fill
* @param res Hexagon resolution (0-15)
* @return number of hexagons to allocate for
*/
int H3_EXPORT(maxPolyfillSize)(const GeoPolygon* geoPolygon, int res) {
// Get the bounding box for the GeoJSON-like struct
BBox bbox;
bboxFromGeofence(&geoPolygon->geofence, &bbox);
int minK = bboxHexRadius(&bbox, res);
// The total number of hexagons to allocate can now be determined by
// the k-ring hex allocation helper function.
return H3_EXPORT(maxKringSize)(minK);
}
/**
* polyfill takes a given GeoJSON-like data structure and preallocated,
* zeroed memory, and fills it with the hexagons that are contained by
* the GeoJSON-like data structure.
*
* The current implementation is very primitive and slow, but correct,
* performing a point-in-poly operation on every hexagon in a k-ring defined
* around the given geofence.
*
* @param geoPolygon The geofence and holes defining the relevant area
* @param res The Hexagon resolution (0-15)
* @param out The slab of zeroed memory to write to. Assumed to be big enough.
*/
void H3_EXPORT(polyfill)(const GeoPolygon* geoPolygon, int res, H3Index* out) {
// One of the goals of the polyfill algorithm is that two adjacent polygons
// with zero overlap have zero overlapping hexagons. That the hexagons are
// uniquely assigned. There are a few approaches to take here, such as
// deciding based on which polygon has the greatest overlapping area of the
// hexagon, or the most number of contained points on the hexagon (using the
// center point as a tiebreaker).
//
// But if the polygons are convex, both of these more complex algorithms can
// be reduced down to checking whether or not the center of the hexagon is
// contained in the polygon, and so this is the approach that this polyfill
// algorithm will follow, as it's simpler, faster, and the error for concave
// polygons is still minimal (only affecting concave shapes on the order of
// magnitude of the hexagon size or smaller, not impacting larger concave
// shapes)
//
// This first part is identical to the maxPolyfillSize above.
// Get the bounding boxes for the polygon and any holes
BBox* bboxes = malloc((geoPolygon->numHoles + 1) * sizeof(BBox));
assert(bboxes != NULL);
bboxesFromGeoPolygon(geoPolygon, bboxes);
int minK = bboxHexRadius(&bboxes[0], res);
int numHexagons = H3_EXPORT(maxKringSize)(minK);
// Get the center hex
GeoCoord center;
bboxCenter(&bboxes[0], ¢er);
H3Index centerH3 = H3_EXPORT(geoToH3)(¢er, res);
// From here on it works differently, first we get all potential
// hexagons inserted into the available memory
H3_EXPORT(kRing)(centerH3, minK, out);
// Next we iterate through each hexagon, and test its center point to see if
// it's contained in the GeoJSON-like struct
for (int i = 0; i < numHexagons; i++) {
// Skip records that are already zeroed
if (out[i] == 0) {
continue;
}
// Check if hexagon is inside of polygon
GeoCoord hexCenter;
H3_EXPORT(h3ToGeo)(out[i], &hexCenter);
hexCenter.lat = constrainLat(hexCenter.lat);
hexCenter.lon = constrainLng(hexCenter.lon);
// And remove from list if not
if (!pointInsidePolygon(geoPolygon, bboxes, &hexCenter)) {
out[i] = H3_INVALID_INDEX;
}
}
free(bboxes);
}
/**
* Internal: Create a vertex graph from a set of hexagons. It is the
* responsibility of the caller to call destroyVertexGraph on the populated
* graph, otherwise the memory in the graph nodes will not be freed.
* @private
* @param h3Set Set of hexagons
* @param numHexes Number of hexagons in the set
* @param graph Output graph
*/
void h3SetToVertexGraph(const H3Index* h3Set, const int numHexes,
VertexGraph* graph) {
GeoBoundary vertices;
GeoCoord* fromVtx;
GeoCoord* toVtx;
VertexNode* edge;
if (numHexes < 1) {
// We still need to init the graph, or calls to destroyVertexGraph will
// fail
initVertexGraph(graph, 0, 0);
return;
}
int res = H3_GET_RESOLUTION(h3Set[0]);
const int minBuckets = 6;
// TODO: Better way to calculate/guess?
int numBuckets = numHexes > minBuckets ? numHexes : minBuckets;
initVertexGraph(graph, numBuckets, res);
// Iterate through every hexagon
for (int i = 0; i < numHexes; i++) {
H3_EXPORT(h3ToGeoBoundary)(h3Set[i], &vertices);
// iterate through every edge
for (int j = 0; j < vertices.numVerts; j++) {
fromVtx = &vertices.verts[j];
toVtx = &vertices.verts[(j + 1) % vertices.numVerts];
// If we've seen this edge already, it will be reversed
edge = findNodeForEdge(graph, toVtx, fromVtx);
if (edge != NULL) {
// If we've seen it, drop it. No edge is shared by more than 2
// hexagons, so we'll never see it again.
removeVertexNode(graph, edge);
} else {
// Add a new node for this edge
addVertexNode(graph, fromVtx, toVtx);
}
}
}
}
/**
* Internal: Create a LinkedGeoPolygon from a vertex graph. It is the
* responsibility of the caller to call destroyLinkedPolygon on the populated
* linked geo structure, or the memory for that structure will not be freed.
* @private
* @param graph Input graph
* @param out Output polygon
*/
void _vertexGraphToLinkedGeo(VertexGraph* graph, LinkedGeoPolygon* out) {
*out = (LinkedGeoPolygon){0};
LinkedGeoLoop* loop;
VertexNode* edge;
GeoCoord nextVtx;
// Find the next unused entry point
while ((edge = firstVertexNode(graph)) != NULL) {
loop = addNewLinkedLoop(out);
// Walk the graph to get the outline
do {
addLinkedCoord(loop, &edge->from);
nextVtx = edge->to;
// Remove frees the node, so we can't use edge after this
removeVertexNode(graph, edge);
edge = findNodeForVertex(graph, &nextVtx);
} while (edge);
}
}
/**
* Create a LinkedGeoPolygon describing the outline(s) of a set of hexagons.
* Polygon outlines will follow GeoJSON MultiPolygon order: Each polygon will
* have one outer loop, which is first in the list, followed by any holes.
*
* It is the responsibility of the caller to call destroyLinkedPolygon on the
* populated linked geo structure, or the memory for that structure will
* not be freed.
*
* It is expected that all hexagons in the set have the same resolution and
* that the set contains no duplicates. Behavior is undefined if duplicates
* or multiple resolutions are present, and the algorithm may produce
* unexpected or invalid output.
*
* @param h3Set Set of hexagons
* @param numHexes Number of hexagons in set
* @param out Output polygon
*/
void H3_EXPORT(h3SetToLinkedGeo)(const H3Index* h3Set, const int numHexes,
LinkedGeoPolygon* out) {
VertexGraph graph;
h3SetToVertexGraph(h3Set, numHexes, &graph);
_vertexGraphToLinkedGeo(&graph, out);
// TODO: The return value, possibly indicating an error, is discarded here -
// we should use this when we update the API to return a value
normalizeMultiPolygon(out);
destroyVertexGraph(&graph);
}