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# Difference Of Squares

Find the difference between the square of the sum and the sum of the squares of the first N natural numbers.

The square of the sum of the first ten natural numbers is
(1 + 2 + ... + 10)² = 55² = 3025.

The sum of the squares of the first ten natural numbers is
1² + 2² + ... + 10² = 385.

Hence the difference between the square of the sum of the first
ten natural numbers and the sum of the squares of the first ten
natural numbers is 3025 - 385 = 2640.



## Source

Problem 6 at Project Euler [http://projecteuler.net/problem=6](http://projecteuler.net/problem=6)

## Submitting Incomplete Solutions
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Version data entries

165 entries across 165 versions & 1 rubygems

Version Path
trackler-2.2.1.78 tracks/kotlin/exercises/difference-of-squares/README.md
trackler-2.2.1.77 tracks/kotlin/exercises/difference-of-squares/README.md
trackler-2.2.1.76 tracks/kotlin/exercises/difference-of-squares/README.md
trackler-2.2.1.75 tracks/kotlin/exercises/difference-of-squares/README.md
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trackler-2.2.1.59 tracks/kotlin/exercises/difference-of-squares/README.md