class String # 'Natural order' comparison of strings, e.g. # # "my_prog_v1.1.0" < "my_prog_v1.2.0" < "my_prog_v1.10.0" # # which does not follow alphabetically. A secondary # parameter, if set to _true_, makes the comparison # case insensitive. # # "Hello.10".natcmp("Hello.1") #=> -1 # # TODO: Invert case flag? # # CREDIT: Alan Davies # CREDIT: Martin Pool # #-- # Adapted from: # # http://sourcefrog.net/projects/natsort/natcmp.rb # # Based on Martin Pool's "Natural Order String Comparison" originally # written in C. (see http://sourcefrog.net/projects/natsort/) # # This implementation is Copyright (C) 2003 by Alan Davies # # # This software is provided 'as-is', without any express or implied # warranty. In no event will the authors be held liable for any damages # arising from the use of this software. # # Permission is granted to anyone to use this software for any purpose, # including commercial applications, and to alter it and redistribute it # freely, subject to the following restrictions: # # 1. The origin of this software must not be misrepresented; you must not # claim that you wrote the original software. If you use this software # in a product, an acknowledgment in the product documentation would be # appreciated but is not required. # 2. Altered source versions must be plainly marked as such, and must not be # misrepresented as being the original software. # 3. This notice may not be removed or altered from any source distribution. # #++ def natcmp(str2, caseInsensitive=false) str1 = self.dup str2 = str2.dup compareExpression = /^(\D*)(\d*)(.*)$/ if caseInsensitive str1.downcase! str2.downcase! end # remove all whitespace str1.gsub!(/\s*/, '') str2.gsub!(/\s*/, '') while (str1.length > 0) or (str2.length > 0) do # Extract non-digits, digits and rest of string str1 =~ compareExpression chars1, num1, str1 = $1.dup, $2.dup, $3.dup str2 =~ compareExpression chars2, num2, str2 = $1.dup, $2.dup, $3.dup # Compare the non-digits case (chars1 <=> chars2) when 0 # Non-digits are the same, compare the digits... # If either number begins with a zero, then compare alphabetically, # otherwise compare numerically if (num1[0] != 48) and (num2[0] != 48) num1, num2 = num1.to_i, num2.to_i end case (num1 <=> num2) when -1 then return -1 when 1 then return 1 end when -1 then return -1 when 1 then return 1 end # case end # while # strings are naturally equal. return 0 end end