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"""This solution for the Zebra Puzzle is adapted from a solution by Peter Norvig for the course "Design of Computer Programs" on Udacity. https://www.udacity.com/course/cs212 """ from itertools import permutations def just_right_of(x, y): return x - y == 1 def next_to(x, y): return abs(x - y) == 1 def solution(): houses = first, _, middle, _, _ = range(5) orderings = list(permutations(houses)) result = next([{Englishman: "Englishman", Spaniard: "Spaniard", Ukranian: "Ukranian", Japanese: "Japanese", Norwegian: "Norwegian"}[x] for x in (water, zebra)] for (red, green, ivory, yellow, blue) in orderings if just_right_of(green, ivory) for (Englishman, Spaniard, Ukranian, Japanese, Norwegian) in orderings if Englishman is red if Norwegian is first if next_to(Norwegian, blue) for (coffee, tea, milk, oj, water) in orderings if coffee is green if Ukranian is tea if milk is middle for (OldGold, Kools, Chesterfields, LuckyStrike, Parliaments) in orderings if Kools is yellow if LuckyStrike is oj if Japanese is Parliaments for (dog, snails, fox, horse, zebra) in orderings if Spaniard is dog if OldGold is snails if next_to(Chesterfields, fox) if next_to(Kools, horse)) return ("It is the {} who drinks the water.\n" "The {} keeps the zebra.").format(*result)
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127 entries across 127 versions & 1 rubygems