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Contents
require File.expand_path('../../../spec_helper', __FILE__)
require File.expand_path('../fixtures/classes', __FILE__)
describe "Enumerable#min_by" do
ruby_version_is '1.8.7' do
it "returns an enumerator if no block" do
EnumerableSpecs::Numerous.new(42).min_by.should be_an_instance_of(enumerator_class)
end
it "returns nil if #each yields no objects" do
EnumerableSpecs::Empty.new.min_by {|o| o.nonesuch }.should == nil
end
it "returns the object for whom the value returned by block is the largest" do
EnumerableSpecs::Numerous.new(*%w[3 2 1]).min_by {|obj| obj.to_i }.should == '1'
EnumerableSpecs::Numerous.new(*%w[five three]).min_by {|obj| obj.length }.should == 'five'
end
it "returns the object that appears first in #each in case of a tie" do
a, b, c = '2', '1', '1'
EnumerableSpecs::Numerous.new(a, b, c).min_by {|obj| obj.to_i }.should equal(b)
end
it "uses min.<=>(current) to determine order" do
a, b, c = (1..3).map{|n| EnumerableSpecs::ReverseComparable.new(n)}
# Just using self here to avoid additional complexity
EnumerableSpecs::Numerous.new(a, b, c).min_by {|obj| obj }.should == c
end
it "is able to return the maximum for enums that contain nils" do
enum = EnumerableSpecs::Numerous.new(nil, nil, true)
enum.min_by {|o| o.nil? ? 0 : 1 }.should == nil
enum.min_by {|o| o.nil? ? 1 : 0 }.should == true
end
end
end
Version data entries
52 entries across 52 versions & 2 rubygems