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require File.expand_path('../../../spec_helper', __FILE__) require File.expand_path('../fixtures/classes', __FILE__) describe "Enumerable#minmax_by" do ruby_version_is '1.8.7' do it "returns an enumerator if no block" do EnumerableSpecs::Numerous.new(42).minmax_by.should be_an_instance_of(enumerator_class) end it "returns nil if #each yields no objects" do EnumerableSpecs::Empty.new.minmax_by {|o| o.nonesuch }.should == [nil, nil] end it "returns the object for whom the value returned by block is the largest" do EnumerableSpecs::Numerous.new(*%w[1 2 3]).minmax_by {|obj| obj.to_i }.should == ['1', '3'] EnumerableSpecs::Numerous.new(*%w[three five]).minmax_by {|obj| obj.length }.should == ['five', 'three'] end it "returns the object that appears first in #each in case of a tie" do a, b, c, d = '1', '1', '2', '2' mm = EnumerableSpecs::Numerous.new(a, b, c, d).minmax_by {|obj| obj.to_i } mm[0].should equal(a) mm[1].should equal(c) end it "uses min/max.<=>(current) to determine order" do a, b, c = (1..3).map{|n| EnumerableSpecs::ReverseComparable.new(n)} # Just using self here to avoid additional complexity EnumerableSpecs::Numerous.new(a, b, c).minmax_by {|obj| obj }.should == [c, a] end it "is able to return the maximum for enums that contain nils" do enum = EnumerableSpecs::Numerous.new(nil, nil, true) enum.minmax_by {|o| o.nil? ? 0 : 1 }.should == [nil, true] end end end
Version data entries
52 entries across 52 versions & 2 rubygems