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# Sublist Given two lists determine if the first list is contained within the second list, if the second list is contained within the first list, if both lists are contained within each other or if none of these are true. Specifically, a list A is a sublist of list B if by dropping 0 or more elements from the front of B and 0 or more elements from the back of B you get a list that's completely equal to A. Examples: * A = [1, 2, 3], B = [1, 2, 3, 4, 5], A is a sublist of B * A = [3, 4, 5], B = [1, 2, 3, 4, 5], A is a sublist of B * A = [3, 4], B = [1, 2, 3, 4, 5], A is a sublist of B * A = [1, 2, 3], B = [1, 2, 3], A is equal to B * A = [1, 2, 3, 4, 5], B = [2, 3, 4], A is a superlist of B * A = [1, 2, 4], B = [1, 2, 3, 4, 5], A is not a superlist of, sublist of or equal to B ## Running the tests To run the tests, run the command `busted .` from within the exercise directory. ## Further information For more detailed information about the Lua track, including how to get help if you're having trouble, please visit the exercism.io [Lua language page](http://exercism.io/languages/lua/about). ## Submitting Incomplete Solutions It's possible to submit an incomplete solution so you can see how others have completed the exercise.
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110 entries across 110 versions & 1 rubygems