/* A JQuery plugin (should this be implemented as a widget instead? not sure)
that will convert a "toggle" form, with single submit button to add/remove
something, like used for Bookmarks, into an AJAXy checkbox instead.
Apply to a form. Does require certain assumption about the form:
1) The same form 'action' href must be used for both ADD and REMOVE
actions, with the different being the hidden input name="_method"
being set to "put" or "delete" -- that's the Rails method to pretend
to be doing a certain HTTP verb. So same URL, PUT to add, DELETE
to remove. This plugin assumes that.
Plus, the form this is applied to should provide a data-doc-id
attribute (HTML5-style doc-*) that contains the id/primary key
of the object in question -- used by plugin for a unique value for
DOM id's.
Uses HTML for a checkbox compatible with Bootstrap 3.
Pass in options for your class name and labels:
$("form.something").blCheckboxSubmit({
//cssClass is added to elements added, plus used for id base
cssClass: "toggle_my_kinda_form",
error: function() {
#optional callback
},
success: function(after_success_check_state) {
#optional callback
}
});
*/
(function($) {
$.fn.blCheckboxSubmit = function(argOpts) {
this.each(function() {
var options = $.extend({}, $.fn.blCheckboxSubmit.defaults, argOpts);
var form = $(this);
form.children().hide();
//We're going to use the existing form to actually send our add/removes
//This works conveneintly because the exact same action href is used
//for both bookmarks/$doc_id. But let's take out the irrelevant parts
//of the form to avoid any future confusion.
form.find('input[type=submit]').remove();
//View needs to set data-doc-id so we know a unique value
//for making DOM id
var uniqueId = form.attr('data-doc-id') || Math.random();
// if form is currently using method delete to change state,
// then checkbox is currently checked
var checked = (form.find('input[name=_method][value=delete]').length != 0);
var checkbox = $('')
.addClass( options.cssClass )
.attr('id', options.cssClass + '_' + uniqueId);
var label = $('