/* A JQuery plugin (should this be implemented as a widget instead? not sure) that will convert a "toggle" form, with single submit button to add/remove something, like used for Bookmarks, into an AJAXy checkbox instead. Apply to a form. Does require certain assumption about the form: 1) The same form 'action' href must be used for both ADD and REMOVE actions, with the different being the hidden input name="_method" being set to "put" or "delete" -- that's the Rails method to pretend to be doing a certain HTTP verb. So same URL, PUT to add, DELETE to remove. This plugin assumes that. Plus, the form this is applied to should provide a data-doc-id attribute (HTML5-style doc-*) that contains the id/primary key of the object in question -- used by plugin for a unique value for DOM id's. Uses HTML for a checkbox compatible with Bootstrap 3. Pass in options for your class name and labels: $("form.something").blCheckboxSubmit({ //cssClass is added to elements added, plus used for id base cssClass: "toggle_my_kinda_form", error: function() { #optional callback }, success: function(after_success_check_state) { #optional callback } }); */ (function($) { $.fn.blCheckboxSubmit = function(argOpts) { this.each(function() { var options = $.extend({}, $.fn.blCheckboxSubmit.defaults, argOpts); var form = $(this); form.children().hide(); //We're going to use the existing form to actually send our add/removes //This works conveneintly because the exact same action href is used //for both bookmarks/$doc_id. But let's take out the irrelevant parts //of the form to avoid any future confusion. form.find('input[type=submit]').remove(); //View needs to set data-doc-id so we know a unique value //for making DOM id var uniqueId = form.attr('data-doc-id') || Math.random(); // if form is currently using method delete to change state, // then checkbox is currently checked var checked = (form.find('input[name=_method][value=delete]').length != 0); var checkbox = $('') .addClass( options.cssClass ) .attr('id', options.cssClass + '_' + uniqueId); var label = $('