ASCIIMathML Formulae
====================

http://www1.chapman.edu/~jipsen/mathml/asciimath.html[ASCIIMathML] is
a clever JavaScript written by Peter Jipsen that transforms
mathematical formulae written in plain text to standard mathematical
notation on an HTML page. See 'Appendix E' in the AsciiDoc User Guide
for more details.

The AsciiDoc `xhtml11` backend supports ASCIIMathML -- it links the
ASCIIMathML script and escapes ASCIIMathML delimiters and special
characters to yield valid XHTML. To use ASCIIMathML:

1. Include the `-a asciimath` command-line option when you run
   `asciidoc(1)`.
2. Enclose ASCIIMathML formulas inside math or double-dollar
   passthroughs or in math passthrough blocks.

Here's the link:asciimath.txt[AsciiDoc source] that generated this
page.

.NOTE
- When you use the `\asciimath:[]` inline macro you need to escape `]`
  characters in the formulas with a backslash, escaping is unnecessary
  if you use the double-dollar macro (for examples see the first two
  formulas below).
- See the
  http://www1.chapman.edu/~jipsen/mathml/asciimath.html[ASCIIMathML]
  website for ASCIIMathML documentation and the latest version.
- If the formulas don't appear to be correct you probably need to
  install the correct math fonts (see the
  http://www1.chapman.edu/~jipsen/mathml/asciimath.html[ASCIIMathML]
  website for details).
- See the link:latexmathml.html[LaTeXMathML page] if you prefer to use
  LaTeX math formulas.

A list of formulas with a mixture of formatting:

- asciimath:[[[a,b\],[c,d\]\]((n),(k))]
- $$`[[a,b],[c,d]]((n),(k))`$$
- asciimath:[x/x={(1,if x!=0),(text{undefined},if x=0):}]
- asciimath:[d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/h]
- Red [red]+++`sum_(i=1)\^n i=(n(n+1))/2`$+++ and [blue]*bold
  asciimath:[int_0\^(pi/2) sinx\ dx=1]*
- [,,1.5]## 1.5 times normal size asciimath:[(a,b\]={x in RR : a < x <= b}]##
- A [,,2]##big## [blue]##blue## formula
  [blue,,2]##asciimath:[x^2+y_1+z_12^34]##.
- [green,yellow,4]##asciimath:[x^2+y_1+z_12^34]##

*********************************************************************
The first three terms factor to give
[red]##asciimath:[(x+b/(2a))^2=(b^2)/(4a^2)-c/a]##.

[red]##asciimath:[x+b/(2a)=+-sqrt((b^2)/(4a^2)-c/a)]##.

Now we take square roots on both sides and get
[red]##asciimath:[x+b/(2a)=+-sqrt((b^2)/(4a^2)-c/a)]##.  Finally we
move the [red]##asciimath:[b/(2a)]## to the right and simplify to get
the two solutions:
[red]*asciimath:[x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)]*.

*********************************************************************