require File.expand_path(File.dirname(__FILE__) + '/spec_helper') describe Timeframe do describe 'initialization' do it 'should create a timeframe using date strings' do tf = Timeframe.new('2008-02-14', '2008-05-10') tf.from.should == Date.parse('2008-02-14') tf.to.should == Date.parse('2008-05-10') end it 'should create a timeframe using date objects' do start = Date.parse('2008-02-14') finish = Date.parse('2008-05-10') tf = Timeframe.new(start, finish) tf.from.should == start tf.to.should == finish end it "should accept months" do timeframe = Timeframe.new(:month => 1) timeframe.from.should == Date.today.change(:month => 1, :day => 1) timeframe.to.should == Date.today.change(:month => 2, :day => 1) end it "should accept month names" do timeframe = Timeframe.new(:month => 'february') timeframe.from.should == Date.today.change(:month => 2, :day => 1) timeframe.to.should == Date.today.change(:month => 3, :day => 1) end it "should accept years" do timeframe = Timeframe.new(:year => 2004) timeframe.from.should == Date.new(2004, 1, 1) timeframe.to.should == Date.new(2005, 1, 1) end it "should accept years and months" do timeframe = Timeframe.new(:year => 2005, :month => 5) timeframe.from.should == Date.new(2005, 5, 1) timeframe.to.should == Date.new(2005, 6, 1) end it "should not accept just one date argument" do lambda { Timeframe.new Date.new(2007, 2, 1) }.should raise_error(ArgumentError, /supply/) end it "should not accept end date that is earlier than start date" do lambda { timeframe = Timeframe.new Date.new(2008, 1, 1), Date.new(2007, 1, 1) }.should raise_error(ArgumentError, /earlier/) end it "should not accept timeframes that cross year boundaries" do lambda { timeframe = Timeframe.new Date.new(2007, 1, 1), Date.new(2008, 1, 2) }.should raise_error(ArgumentError, /cross/) end it "should optionally accept timeframes that cross year boundaries" do lambda { timeframe = Timeframe.new Date.new(2007, 1, 1), Date.new(2008, 1, 2), :skip_year_boundary_crossing_check => true }.should_not raise_error end end describe '#inspect' do it 'should return the time frame in readable text' do start = Date.parse('2008-02-14') finish = Date.parse('2008-05-10') tf = Timeframe.new(start, finish) tf.inspect.should =~ // end end describe '.constrained_new' do let(:start) { Date.parse('2008-02-14') } let(:finish) { Date.parse('2008-05-10') } let(:constraint_start) { Date.parse('2008-01-01') } let(:constraint_finish) { Date.parse('2008-12-01') } let(:constraint) { Timeframe.new(constraint_start, constraint_finish) } it "should allow for constrained creation" do constraint = Timeframe.new :year => 2008 may = Timeframe.new Date.new(2008,5,1), Date.new(2008,6,1) january = Timeframe.new Date.new(2008,1,1), Date.new(2008,2,1) Timeframe.constrained_new(may.from, may.to, constraint).should == may Timeframe.constrained_new(Date.new(2007,1,1), Date.new(2010,1,1), constraint).should == constraint Timeframe.constrained_new(Date.new(2007,11,1), Date.new(2008,2,1), constraint).should == january end it 'should return a timeframe spanning start and end date if within constraint' do tf = Timeframe.constrained_new(start, finish, constraint) tf.from.should == start tf.to.should == finish end it 'should return a timeframe spanning constraint start and end date if outside constraint' do constraint = Timeframe.new(start, finish) tf = Timeframe.constrained_new(constraint_start, constraint_finish, constraint) tf.from.should == start tf.to.should == finish end it 'should return a timeframe starting at constraint start' do start = Date.parse('2008-01-01') constraint_start = Date.parse('2008-01-14') constraint = Timeframe.new(constraint_start, constraint_finish) tf = Timeframe.constrained_new(start, finish, constraint) tf.from.should == constraint_start tf.to.should == finish end it 'should return a timeframe ending at constraint end' do constraint_finish = Date.parse('2008-04-14') constraint = Timeframe.new(constraint_start, constraint_finish) tf = Timeframe.constrained_new(start, finish, constraint) tf.from.should == start tf.to.should == constraint_finish end it "should return a 0-length timeframe when constraining a timeframe by a disjoint timeframe" do constraint = Timeframe.new :year => 2010 timeframe = Timeframe.constrained_new( Date.new(2009,1,1), Date.new(2010,1,1), constraint) timeframe.days.should == 0 end end describe '.this_year' do it "should return the current year" do Timeframe.this_year.should == Timeframe.new(:year => Time.now.year) end end describe '#days' do it "should return them number of days included" do #TODO: make these separate "it" blocks, per best practices Timeframe.new(Date.new(2007, 1, 1), Date.new(2008, 1, 1)).days.should == 365 Timeframe.new(Date.new(2008, 1, 1), Date.new(2009, 1, 1)).days.should == 366 #leap year Timeframe.new(Date.new(2007, 11, 1), Date.new(2007, 12, 1)).days.should == 30 Timeframe.new(Date.new(2007, 11, 1), Date.new(2008, 1, 1)).days.should == 61 Timeframe.new(Date.new(2007, 2, 1), Date.new(2007, 3, 1)).days.should == 28 Timeframe.new(Date.new(2008, 2, 1), Date.new(2008, 3, 1)).days.should == 29 Timeframe.new(Date.new(2008, 2, 1), Date.new(2008, 2, 1)).days.should == 0 end end describe '#include?' do it "should know if a certain date is included in the Timeframe" do #TODO: make these separate "it" blocks, per best practices timeframe = Timeframe.new :year => 2008, :month => 2 [ Date.new(2008, 2, 1), Date.new(2008, 2, 5), Date.new(2008, 2, 29) ].each do |date| timeframe.include?(date).should == true end [ Date.new(2008, 1, 1), Date.new(2007, 2, 1), Date.new(2008, 3, 1) ].each do |date| timeframe.include?(date).should == false end end end describe '#==' do it "should be able to know if it's equal to another Timeframe object" do Timeframe.new(:year => 2007).should == Timeframe.new(:year => 2007) Timeframe.new(:year => 2004, :month => 1).should == Timeframe.new(:year => 2004, :month => 1) end it "should hash equal hash values when the timeframe is equal" do Timeframe.new(:year => 2007).hash.should == Timeframe.new(:year => 2007).hash Timeframe.new(:year => 2004, :month => 1).hash.should == Timeframe.new(:year => 2004, :month => 1).hash end end describe '#months' do it "should return an array of month-long subtimeframes" do Timeframe.new(:year => 2009).months.length.should == 12 end it "should not return an array of month-long subtimeframes if provided an inappropriate range" do lambda { Timeframe.new(Date.new(2009, 3, 2), Date.new(2009, 3, 5)).months }.should raise_error(ArgumentError, /whole/) lambda { Timeframe.new(Date.new(2009, 1, 1), Date.new(2012, 1, 1), :skip_year_boundary_crossing_check => true).months }.should raise_error(ArgumentError, /dangerous during/) end end describe '#year' do it "should return the relevant year of a timeframe" do Timeframe.new(Date.new(2009, 2, 1), Date.new(2009, 4, 1)).year.should == Timeframe.new(:year => 2009) end it "should not return the relevant year of a timeframe if provided an inappropriate range" do lambda { Timeframe.new(Date.new(2009, 1, 1), Date.new(2012, 1, 1), :skip_year_boundary_crossing_check => true).year }.should raise_error(ArgumentError, /dangerous during/) end end describe '#&' do it "should return its intersection with another timeframe" do #TODO: make these separate "it" blocks, per best practices (Timeframe.new(:month => 4) & Timeframe.new(:month => 6)).should be_nil (Timeframe.new(:month => 4) & Timeframe.new(:month => 5)).should be_nil (Timeframe.new(:month => 4) & Timeframe.new(:month => 4)).should == Timeframe.new(:month => 4) (Timeframe.new(:year => Time.now.year) & Timeframe.new(:month => 4)).should == Timeframe.new(:month => 4) (Timeframe.new(Date.new(2009, 2, 1), Date.new(2009, 6, 1)) & Timeframe.new(Date.new(2009, 4, 1), Date.new(2009, 8, 1))).should == Timeframe.new(Date.new(2009, 4, 1), Date.new(2009, 6, 1)) end end describe '#/' do it "should return a fraction of another timeframe" do (Timeframe.new(:month => 4, :year => 2009) / Timeframe.new(:year => 2009)).should == (30.0 / 365.0) end end describe '#gaps_left_by' do it "should be able to ascertain gaps left by a list of other Timeframes" do Timeframe.new(:year => 2009).gaps_left_by( Timeframe.new(:year => 2009, :month => 3), Timeframe.new(:year => 2009, :month => 5), Timeframe.new(Date.new(2009, 8, 1), Date.new(2009, 11, 1)), Timeframe.new(Date.new(2009, 9, 1), Date.new(2009, 10, 1)) ).should == [ Timeframe.new(Date.new(2009, 1, 1), Date.new(2009, 3, 1)), Timeframe.new(Date.new(2009, 4, 1), Date.new(2009, 5, 1)), Timeframe.new(Date.new(2009, 6, 1), Date.new(2009, 8, 1)), Timeframe.new(Date.new(2009, 11, 1), Date.new(2010, 1, 1)) ] end end describe '#covered_by?' do it "should be able to ascertain gaps left by a list of other Timeframes" do Timeframe.new(:year => 2009).covered_by?( Timeframe.new(:month => 1, :year => 2009), Timeframe.new(Date.new(2009, 2, 1), Date.new(2010, 1, 1)) ).should be_true end end describe '#last_year' do it "should return its predecessor in a previous year" do Timeframe.this_year.last_year.should == Timeframe.new(Date.new(Date.today.year - 1, 1, 1), Date.new(Date.today.year, 1, 1)) end end describe 'Timeframe:class#interval' do it 'should parse ISO 8601 interval format' do Timeframe.interval('2009-01-01/2010-01-01').should == Timeframe.new(:year => 2009) end it 'should skip year boundary checking' do lambda { Timeframe.interval '2009-01-01/2011-01-01' }.should_not raise_error end it 'should understand its own #to_param' do t = Timeframe.new(:year => 2009) Timeframe.interval(t.to_param).should == t end end describe 'Timeframe:class#from_json' do it 'should understand its own #to_json' do t = Timeframe.new(:year => 2009) Timeframe.from_json(t.to_json).should == t end end describe '#to_json' do it 'should generate JSON (test fails on ruby 1.8)' do Timeframe.new(:year => 2009).to_json.should == "2009-01-01/2010-01-01" end end describe '#to_param' do it 'should generate a URL-friendly parameter' do Timeframe.new(:year => 2009).to_param.should == "2009-01-01/2010-01-01" end end describe '#to_s' do it 'should not only look at month numbers when describing multi-year timeframes' do Timeframe.multiyear(Date.parse('2008-01-01'), Date.parse('2010-01-01')).to_s.should == "the period from 01 January to 31 December 2009" end end end